Find two consecutive odd intergers whose sum is 116

x+(x+2)=116. Simplify that to 2x+2=116, subtract 2 from both sides to get 2x=114, and then divide both sides by 2 to get x=57. That would be the first integer, so the second would then be 59. So there's your The two consecutive odd integers are 57 and 59.

Step-by-step explanation:

(x3 + 6x2 + 2x - 6) • (x - 1)

step-by-step explanation:

polynomial long division :

3.2     polynomial long division

dividing :   x4+5x3-4x2-8x+6

                              ("dividend")

by         :     x-1     ("divisor")

dividend     x4   +   5x3   -   4x2   -   8x   +   6

- divisor   * x3     x4   -   x3            

remainder         6x3   -   4x2   -   8x   +   6

- divisor   * 6x2         6x3   -   6x2        

remainder             2x2   -   8x   +   6

- divisor   * 2x1             2x2   -   2x    

remainder               -   6x   +   6

- divisor   * -6x0               -   6x   +   6

remainder                     0

quotient :   x3+6x2+2x-6   remainder:   0

yes because they have the same amount of green and blur marbles.

step-by-step explanation: