Arectangular field is four times as long as it is wide. if the perimeter of the field is 550 feet, what are the dimensions of the field? a) write an equation you can use to answer the given question. let w be the width of the field.

The equation used to find length and width is: 550 = 2(4w+w)

Length = 220 feet

Width = 55 feet

Step-by-step explanation:

Let width = w

Length = 4w

Perimeter = 550 feet

We know that Perimeter of rectangle is

Perimeter of rectangle = 2(length + width)

Putting values of length and width

Perimeter of rectangle = 2(length + width)

550 = 2(4w+w)

550 = 2(5w)

550 = 10 w

=> w = 550/10

w = 55

So, width is 55 feet

Now, finding length:

Length = 4w

Length = 4(55)

Length = 220 feet

So, The equation used to find length and width is: 550 = 2(4w+w)

Length = 220 feet

Width = 55 feet

12 servings. 4 times 3= 12