An air traffic controller is tracking two planes. to start, plane a was at an altitude of 352 meters, and plane b was just taking off. plane a is gaining altitude at 14 meters per second, and plane b is gaining altitude at 22 meters per second.
let be the number of seconds that have passed.
(a)for each plane, write an expression for the altitude of the plane after seconds.
altitude of plane a (in meters) =
altitude of plane b (in meters) =
(b)write an equation to show that the two planes are at the same altitude.

answer: the price of one pound cabbage = $ 0.8

the point (10,8) represents that the cost of 10 pounds cabbage is $ 8

step-by-step explanation:

since, here is a proportional relation between the number of pounds of cabbage (x) and the price in dollars (y).

therefore, we can write,

⇒ y = k x

where k is the constant of proportionality.

now, point (5,4) is in the line.

thus, it will satisfies the above equation of line.

⇒ 4 = 5 k

⇒ k = 0.8

thus, the equation of the line is,

y = 0.8 x

a) for x = 1,

y = 0.8

therefore, the cost of one pound of cabbage is 0.8 dollars.

b) in the below graph (10,8) represents that the cost of 10 pounds of cabbage is 8 dollars.

10.416 m/s

step-by-step explantion:

distance=100m

time= 9.6s

average speed=100/9.6

=10.416 m/s

faster, im not sure why but i know it is faster