Albinism is a recessive trait. a man and woman both show normal pigmentation, but both have one parent who has albinism (without melanin pigmentation). what is the probability that their first child will have albinism?

0,25

Step-by-step explanation:

As both the man and the woman have one parent who has albinism, they have the gene (though recessive). The genetic information is given 50% by each parent. The probability of the first child to have albinism is given by the probability of both parent to transfer the gene to him. It is:

P(W=yes ∩ M=yes) ;

where

P= probability

W= woman

∩ = intersection

M = man

Using the property of intersection in probability (when independient events), we have:

P(W=yes ∩ M=yes) = P(W=yes) × P(M=yes) = 0,5 × 0,5 = 0,25

step-by-step explanation:

-362

step-by-step explanation:

(12)(4)+2(12)-34(12)+2(12)-3

  \/         \/         \/         \/

  48 +   24 -   408 + 24 - 3

      \   /               \   /

          72     -     432 - 3 = -363