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solve the equation p^2 + 10p = 1 by completing the square method. show your work.

p = -5 ± √26

Step-by-step explanation:

p² + 10p = 1

To complete the square, start by making the leading coefficient 1 (it already is).

Next, take half of the b coefficient, square it, and add the result to both sides.

(10/2)² = 5² = 25

p² + 10p + 25 = 1 + 25

p² + 10p + 25 = 26

Factor:

(p + 5)² = 26

Solve:

p + 5 = ±√26

p = -5 ± √26

hello from mrbilldoesmath!

answer:   (7x + 6y) ( 49x^2 - 42xy + 36y^2)

discussion:

in general, the factorization of a^3 + b^3 is

a^3 + b^ 3 = (a + b) ( a^2 - ab + b^2)

in our case note that 343 = 7^3 and 216 = 6^3 so the equation becomes:

343x^3 + 216y^3 = (7x)^3 + (6y)^3

if you think of a (above) as 7x and b as 6y the factorization becomes

343x^3 + 216y^3 =

((7x + 6y) (   (7x)^2 - 7x*6y + (6y)^2)   =

(7x + 6y) ( 49x^2 - 42xy + 36y^2)

you,

mrb

(a + b) (a^2 - a b + b^2)

113.42

i hope that is right.

step-by-step explanation: