If θ is a first-quadrant angle in standard position with p(u, v) = (3, 4), evaluate cos 2 θ . -7/25 -1/5 7/25

-7/25.

Step-by-step explanation:

From the given point P we see that the hypotenuse =  √(3*2 + 4^2) = 5.

So cos  θ = 3/5

cos 2 θ =  2 cos^2 θ - 1

= 2 * (3/5)^2 -1

= -7/25.

b

step-by-step explanation:

the rocket cannot penetrate the ground, in a contextual sense, therefore the roots of this equation should be the domain of this function. i'll let you find the roots of this quadratic equation (hint: use the quadratic formula:  

1- c

2-a

step-by-step explanation:

mark brainliest!