Is the number of members of club x greater than the number of members of club y ? (1) of the members of club x, 20 percent are also members of club y. (2) of the members of club y, 30 percent are also members of club x.

Yes

Step-by-step explanation:

The 20% of members of club X that are also members of club Y can be written as: P(Y/X) = 20% (that is, the probability of belonging to Y given that it belongs to X)

The 30% of members of club Y that are also members of club X can be written as: P(X/Y) = 30% (that is, the probability of belonging to X given that it belongs to Y)

The formula of conditional probability of A given B is  

P(A/B) = (A∩B) / P(A)

Where (A∩B) is the probability that both events A and B occur and P(A) is the probability of A.

Based on that, we can write,

P(Y/X) = P(Y∩X) / P(X) = 20 % = 0.2

P(X/Y) = P(Y∩X) / P(Y) = 30 % = 0.3

Clearing P(Y∩X) of both equations and equalizing,

P(Y/X).P(X) = P(X/Y).P(Y)

Moving terms ,

P(X) / P(Y) = P(X/Y) / P(Y/X) = 0.3 / 0.2 = 1.5

That is, P(X) is 1.5 times P(Y), which means that the amount of members of X is greater than the members of Y.  

if this is really you s much. i only have 3 points left and i have 2 questions to ask

location: point 0

step-by-step explanation:

well, -8 to 10 on a number line is 18 spaces.

1/9 of 18 is 2.

so, 4/9 of 18 must be 8.

8 spaces from -8 (a) is 0.

so, 4/9 of the way from -8 to 10 is 0!