(t^-4)^-9 t^2
a t^26
b t^-26
c t^38
d t ^-38

Its c

Step-by-step explanation:

The relevant rules of exponents are

.. (t^a)^b = t^(a·b)

.. t^a·t^b = t^(a+b)

You have

.. (t^-4)^-9·t^2  

.. = t^((-4)*(-9) +2)

.. = t^38 . . . . . . . . . . . selection C

the two may have that, even a breakdown is probably offered

step-by-step explanation:

given that there are two triangles j'k'l' and jkl>

the former is got by dilating the second one.

when drawn on a grid, (graph paper) coordinates of vertices of first triangle is

(6,12)j, (9,6)k and (12,9)l

side jk has length = distance between j and k

=

side j'k'=distance between j' and k'

=

ie j'k'l' has sides 1/3 of that of corresponding sides of jkl.

hence scale factor of 1/3 is used to get j'k'l'from jkl