License plates in india begin with a code that identifies the state and district where the vehide is registered, and this code is followed by a four-digit identification number. these identification numbers are given sequentially, starting with , 0001, 0002, etc. once this sequence reaches , a letter from the set (a, ) is added (in order), and once these run out, additional letters are added, and so on. so the sequence of identification numbers proceeds as follows: , , adoo, 1, 8, 80001, 2 20001, , aa, aa0001, (a) how many identification numbers are there using two or fewer letters? (b) if a district registers 10 million cars, how many identification numbers must have three letters? (c) suppose a district registers 406,250 cars. what percentage of identification numbers have exactly one letter? (d) suppose a district registers 500,000 cars. what percentage of identification numbers have no letters? (e) suppose you see a plate in bangalore, india, with the identification number cr9535. how many vehicles were registered in this district before the vehicle with this plate?

a.7,030,000 license plates

b.2,970,000

c.64%

d.2%

e.969535 plates

Step-by-step explanation:

(a)  We must add the number of possible plates with no letter with ne letter and with 2 letters to account for all using 2 or fewer letters:

10*10*10*10 for the no-letters, ranging from 0 to 9999=10000

26*10*10*10*10 for each of the 26 letters there can be 10000 plates = 260000

26*26*10*10*10*10 for the two letters plates.=6760000.

The sum of the 3 is 7,030,000 license plates.

b) if a state registers 10 million plates, the number of plates with 3 letter will be 10 millions minus the amount of plates that have less than 3 letters, which we calculated previously.

10000000-7030000=2,970,000

c)if a state registers 406,250 cars and we know that one letter plates make 260000 we can use a three rule to detenime the percentage

406,250100%

260000x=26,000,000/406,250= 64%

d)as before we know how many plates can have no letters, so we do a three rule again:

500,000100%

10,000x=1,000,000/500,000=2%

e) We will do this in parts:

From CR0000 to CR9535 there are 9535 cars before (accounting for 0000)

Between CA0000 TO CR0000 there are 17 letters, with 10000 plates each= 170000

Betwen 0000 and CA0000 we have: 10000 for the plates with no letter, 260000 for the plates with one, and 2*260000 for letters A and B followed by another letter: 10000+260000*3=790000

Adding all these numbers: 790000+170000+9535=969535 plates

sorry man i accidentally pressed yes my bad

step-by-step explanation: