Aray of light with intensity lo falls vertically on the sur face of the sea and at ten meters deep its intensity is 10/3. assume that the loss of light intensity is a process with a constant rate : a)calculate the intensity of the light at 50 and 100 meters deep. b) at what depth will 1/100 of the initial intensity remain?

intensity =

intensity =

depth = 333.33 m

Step-by-step explanation:

given data

deep = 10 m

intensity = Io

intensity = Io/3

to find out

intensity of light at 50 m and 100 m and 1/100 of initial intensity remain ?

solution

we know here that intensity is inversely proportional to deep so

intensity = k ×      .................1

here k is constant

so we have given 10 m deep so

 =

so k = Io ×    ................2

so from equation 1 when 100 m deep and 50 m deep

intensity = k ×

intensity =  Io × ×

intensity =

and

intensity =  Io × ×

intensity =

and

at intensity Io/100

intensity = k ×

 =  Io × ×

D = 333.33 m

so depth = 333.33 m

the answer is 24

step-by-step explanation:

4

step-by-step explanation:

6 (donuts) divided by 3 is 2.

so 2/3 means 2 times 2, which is 4/6.

you get two and your friend gets four.