Let n > 5. a deck containing 4n cards has exactly n cards each of four diffrent suits numbered from the set [n]. using the method of choice (or otherwise) in how many ways can five cards be chosen so that they contain: (a) five consecutive cards of the same suit? (ie. the set of numbers on the cards is li, i +41) (b) four of the five cards have the same number? (c) exactly three of the cards have the same number? (d) not more than two cards of the same suit? hint: consider two cases.