Mathematics, 09.09.2019 01:10 tanabugg
Solve the equation on the interval [0, 2π).
tan^2x sin x = tan^2x
a. π/2, π
b. 0, π/2
c. 0, π
d. π/2, 2π
Answers: 1
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Solve the equation on the interval [0, 2π).
tan^2x sin x = tan^2x
a. π/2, π
b. 0,...
tan^2x sin x = tan^2x
a. π/2, π
b. 0,...
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