Which of the following steps is included in the construction of a perpendicular line through a point on a line?
connect arcs that are above and below the given line with a straightedge.
connect arcs that are above the original line with a straightedge.
create arcs on either side of a point that is off the given line.
create a copied angle by using the first two lines as the original angle.

Connect arcs that are above the original line with a straightedge ⇒ 2nd

Step-by-step explanation:

* Lets revise how to construct a perpendicular line through a point

 on the line

- Given: line AB and point P lies on it

1. Place your compass pin at P and draw an arc of any size below  

  AB that crosses the line twice at points C and D  

2. Stretch the compass to a larger distance

3. Place the compass pin on point C and draw a small arc above 

   the line  

4. Without changing the distance of the compass place the  

   compass pin on point D and draw another small arc intersects

   the small arc  from C at point E

5. Using a straightedge, to join P which is on the original line and E

    which is the intersection point of the two small arcs above the

    original line, then PE is perpendicular to AB  at E

- From the steps up the step is including in the construction of a

 perpendicular line through a point on a line is:

 Connect arcs that are above the original line with a straightedge

* Remember:

- The step of Connect arcs that are above and below the given line

  with a straightedge is in the construction a perpendicular from a

  point off the line

- The step of Create arcs on either side of a point that is off the

  given line is in the construction of a perpendicular bisector

  of a line

- The step of Create a copied angle by using the first two lines as the

  original angle in the construction of the parallel lines

- Look to the attached figure to help you

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this

i think asking google will you get the answer to that question