Hector drew nop with the coordinates (4,2) (5,3) , and (6,2) then he drew an image of this triangle with coordinates (-4,2) -5,3) and (-6,2) what is the line of reflection for this image

The line of reflection for this image is the y-axis

Step-by-step explanation:

we know that

The rule of a reflection of a point across the y-axis is equal to

(x,y) > (-x,y)

In this problem we have

the coordinates (4,2),(5,3) and (6,2)

Applying reflection across the y-axis

(4,2) > (-4,2)

(5,3) > (-5,3)

(6,2) > (-6,2)

therefore

The line of reflection for this image is the y-axis

the value of v.w= -12.

step-by-step explanation:

we are given three vector r,v and w as:

r = < 5, -5, -2> ; v = < 2, -8, -8> ; w = < -2, 6, -5>

we know that r,v and w could also be represented as:

r=5i-5j-2k

v=2i-8j-8k

and w= -2i+6j-5k

where i,j and k are the unit vectors of x,y and z-axis respectively.

also we know that it has the following property:

i.i=1 ; j.j=1; k.k=1

and i.=j.i=i.k=k.i=j.k=k.j=0

i.e. when we multiply two vectors or we find it's dot product we need to only multiply the components of x coordinates with each other; y with each other and z with each other.

hence, v.w= (2i-8j- -2i+6j-5k)

                  = 2×(-2)+(-8)×(6)+(-8)×(-5)

                  = -4-48+40

                  = -12

hence, v.w= -12

3.how is solving radical equations different than solving linear equations?

step-by-step explanation: