Atrain on a straight track goes in the positive direction for 6.7 km , and then backs up for 4.0 km . is the distance covered by the train greater than, less than, or equal to its displacement?

Distance is greater than the displacement.

Step-by-step explanation:

We are given that a train on a straight track goes in the positive direction.

We have to find that distance covered by the train is greater than, lees than or equal to its displacement.

Train covered distance in positive direction=6.7 km

Train covered distance in back=4.0 km

Distance covered by the train=6.7+4=10.7 Km

Because distance is the length of path covered by object.

Displacement =Final position -Initial position

Displacement =6.7-4=2.7 km

        10.7 > 2.7

Distance > Displacement

Hence, Distance is greater than the displacement.

c. 27 units.

step-by-step explanation:

we are told that in circle a, ∠bae ≅ ∠dae.

we can see from our given diagram that in and ;

, as these are radii of our given circle.

therefore, by sas congruence postulate.

hence, side be will be equal to side de as corresponding parts of congruent triangles are congruent. so we can set an equation to find the value of x as:

now let us substitute x=17 in the expression for the length of be.

therefore, length of be will be 27 units and option c is the correct choice.