The area of a rectangular room is 750 square feet. the width of the room is 5 feet less than the length of the room. the area of a rectangular room is 750 square feet. the width of the room is 5 feet less than the length of the room. which equations can be used to solve for y, the length of the room? select three options. y(y + 5) = 750 y2 – 5y = 750 750 – y(y – 5) = 0 y(y – 5) + 750 = 0 (y + 25)(y – 30) = 0

Step-by-step explanation:

Givens

Let's call the width and the length. According to the problem they are related as follows

, because the width is 5 feet less than the lenght.

We know that the area of the room is defined as

Where

Replacing the given area and the expression, we have

We need to find two number which product is 750 and which difference is 5, those numbers are 30 and 25.

Using the zero property, we have

Where only the positive number makes sense to the problem because a negative length doesn't make any sense.

Therefore, the length of the room is 30 feet.

Also, the right answers are the second choice where , the third choice and the last choice.

answer: lol haha i'm in flvs too!

but to answer question number 1 would be a.

and number 2 would be c.