1.give one number that makes the inequality x + 7 > 20 true
2.give one number that makes the inequality 3x < 25 true
3.what is the minimum number of 60 passenger buses needed to transport 200 students?
4.what is the least number of boxes needed to package 300 candies if each box will hold 16 candies?

1. Any number above 13 works. Why? Because 20-7=13, and to be greater than 20, you must add a number larger than 13.

Examples: 14+7 > 20, 30+7 > 20, 100+7 > 20

2. Any number below 25/3 (which is also 8.3 with a repeating 3) works. Why? Because 25/3=8.3 with a repeating 3, and to remain less than 25, you must multiply by a number less than 8.3 with a repeating 3.

Examples: 3(8) < 25, 3(5) < 25, 3(0) < 25

3. 4 buses. 1 bus will hold 60 students, 2 will hold 120, 3 will hold 180, and 4 will hold 240. The question is trying to trick you into putting now 3.3333333333... buses because that's what 200/60 is, but there is no such thing as a third of a bus. So you need at least 4 buses. (There will be an extra 40 spaces for passengers on the 4th bus, but that is okay.)

To find this answer I did 200/60 and got 3.3 with a repeating 3. You must round to the higher whole number. Rounding down to 3 buses leaves you with 20 students without a bus.

4. 19 boxes. 18 boxes will only hold 288 candies. The question is trying to trick you into putting down 18.75 boxes because that's what 300/16 is, but there is no such thing as 75% of a box. So you need at least 19 boxes. (There will be an extra 4 spaces for candies in the 19th box, but that is okay.)

To find this answer I did 300/16 and got 18.75. You must round to the higher whole number. Rounding down to 18 boxes leaves you with 12 candies without a box.

29933333.33

step-by-step explanation:

6×10=604000000÷60=66666.6666766666.6667×449=29933333.33