Write the equation of the line in slope- intercept form that is parallel given the equation and point.

the desired equation is y = (-2/5)x + 5

Step-by-step explanation:

We want the equation of the line that has the same slope as y = (-2/5)x + 15 and which also passes thru the point (10, 1).

Starting with y = mx + b, substute (-2/5) for m, 10 for x and 1 for y:

1 = (-2/5)(10) + b, or:

1 = -4 + b.  Thus, b = 5, and the desired equation is y = (-2/5)x + 5.

b is 38 degrees.

a is 52 degrees.

this is because if b is 38 and a is 14 degrees more than b than 38+14=52 and 52+38=90 degrees. hope this .

-232

step-by-step explanation: