Renaldo catches the bus at 4: 00 pm to ride 3.2 miles from his house to the dentists office. he arrives at 4: 30 pm, for a one hour appointment. then he will ride a bus traveling at te same rate of speed for 4.8 miles to the soccer field. will he be on time for his 6: 30 pm soccer practice?

Step-by-step explanation:

speed = distance/time

so renaldo speed = 3.2/0.5 = 6.4miles/hr (since time taken is 1/2 hr)

now after 1 hr of his appoinment i.e at 5:30pm he took bus whose speed is same as before i.e 6.4 miles/hr

now time taken to cover this 4.8 miles = 4.8/6.4 = 3/4 hr (since time = distance /speed )

3/4 hr = 3/4 * 60 = 45 minutes

so he reached at 6:15pm . so he will be on time.

you have to put the graph on here with the question

step-by-step explanation: