Disks of polycarbonate plastic from a supplier are analyzed for scratch and shock resistance. the results from 100 disks are summarized as follows:
shock resistance
scratch resistance high low
high 70 9
low 16 5
let a denote the event that a disk has high shock resistance, and let b denote the event that a disk has high scratch resistance. if a disk is selected at random, determine the following probabilities. input your answers in the fractional form (do not simplify).
p(a)=86/100
p(b)=79/100
p(a')=7/50
p(a u b)=95/100
p(a' u b)=

0.84

Step-by-step explanation:

Given that Disks of polycarbonate plastic from a supplier are analyzed for scratch and shock resistance. The results from 100 disks are summarized as follows:

P(A) = 0.86, P(B) = 0.79, P(A') = 0.14, P(AUB) = 0.95

We are to find out P(A'UB)

We have

P(A \bigcap B)" alt="P(A'UB)=0.14+0.79-0.79+0.70\\=0.84" />P(A \bigcap B)" />

dc=6 square root of 3 and ac is 12 square root 3

c and d

step-by-step explanation:

square root of 3/2 = 18/c

cross multiply to get 18*2=√3*c

36/√3 * √3/√3 = c

c= 36*√3/3

c=12√3

3/6 chance

step-by-step explanation:

half of the nubers are odd numbers (1,3,5) which in that case if you would be told to simplify it would be 1/2