In what career would you most likely apply concepts from geometry?

- Architect

- Cartographer and Photogrammetrist

- Drafter

- Mechanical Engineer

- Surveyor

- Urban and Regional Planner

Step-by-step explanation:

Architects utilize geometric principles while designing layouts for their ongoing projects, which can include buildings, electrical systems, and plumbing architecture.

Cartographers utilize geographic data to create or update maps for use in education, as well as environmental presentations.

Using the same geometric knowledge and applications as architects and engineers, drafters create design plans with the use of computer-aided design (CAD) software.

Mechanical engineers, some of the most diversified engineers, use a multitude of geometric concepts to design mechanical devices, or update existing structures.

Surveyors use geometry to take exact measurements of boundaries for different types of property.

Urban and regional planners rely on the same geometry practices used by surveyors when examining the positives and negatives of introducing new and updated plans for a community.

* Not my own words. This is the website if you need more info;

https://study.com/articles/jobs_that_involve_geometry.html

Architect and probably alot others. Please thank me

Step-by-step explanation:

a.   we have two

lines:   y = 4-x   and  

y = 8-x^-1

given two simultaneous equations that are both to be

true, then the solution is the points where the lines cross. the intersection is

where the two equations are equal. therefore the solution that works for both

equations is when

4-x = 8-x^-1

this is where the two lines will cross and that is the

common point that satisfies both equations.

b.   4-x = 8-x^-1

  x           4-x       8-x^-1

-3           7        

8.33

-2           6         8.5

-1           5         9

  0           4        

-

  1           3        

7

  2           2        

7.5

  3           1         7.67

the table shows that none of the x values from -3 to 3 is

the solution because in no case does

4-x = 8-x^-1

to find the solution we need to rearrange the equation to

find for x:

4-x = 8-x^-1

multiply both sides with x:

4x-x^2 = 8x-1

x^2+4x-1=0

x= -4.236, 0.236

therefore there are two points that satisfies the

equation.

find y:  

x=-4.236

y = 4-x   = 4 – (-4.236)

= 8.236

y = 8-x^-1 =   .236)^-1

= 8.236

x=0.236

  y = 4-x   = 4 – (0.236) = 3.764

y = 8-x^-1 =   8-(0.236)^-1

= 3.764

thus the two lines cross at 2 points:

(-4.236, 8.236) & (0.236, 3.764)

c.   to solve

graphically the equation 4-x = 8-x^-1

we would graph both lines: y = 4-x   and   y

= 8-x^-1

the point on the graph where the lines cross is the

solution to the system of equations.

just graph the points on part b on a cartesian coordinate

system and extend the two lines.   the

solution is, as stated, the point where the two lines cross on the graph.

step-by-step explanation:

mark brainliest!