Which graph represents the solution set for the inequality startfraction one-half endfraction x is less than or equal to 18.x ≤ 18? a number line from 0 to 10 in increments of 1. a point is at 9 and a bold line starts at 9 and is pointing to the right. a number line from 0 to 60 in increments of 6. a point is at 36 and a bold line starts at 36 and is pointing to the right. a number line from 0 to 10 in increments of 1. a point is at 9 and a bold line starts at 9 and is pointing to the left. a number line from 0 to 60 in increments of 6. a point is at 36 and a bold line starts at 36 and is pointing to the left.

A number line from 0 to 60 in increments of 6. A point is at 36 and a bold line starts at 36 and is pointing to the left. ⇒ last answer

Step-by-step explanation:

* Lets explain how to solve the problem

- When solving an inequality, there are some important points:

# If the inequality is x > a, then it represented on the number line by

  a ray with empty small circle as end starts at a and pointed to

  the right (⇒ ∞)

# If the inequality is x ≥ a, then it represented on the number line by

  a ray with bold small circle as end starts at a and pointed to the

  right (⇒ ∞)

# If the inequality is x < a, then it represented on the number line

  by a ray with empty small circle as end starts at a and pointed to

  the left (⇒ -∞)

# If the inequality is x ≤ a, then it represented on the number line by

  a ray with bold small circle as end starts at a and pointed to the

  left (⇒ -∞)

* Lets solve the problem

∵ 1/2 x ≤ 18

- Multiply both sides by 2

∴ x ≤ 36

- To represent it draw a number line from 0 to 60 and the counted

 by 6 as 0, 6, 12, 18, 24, 30, 36, 42, 48, 54, 60

- Draw a ray with bold end starts at 36 and pointed to the left

∴ A number line from 0 to 60 in increments of 6. A point is at 36 and

  a bold line starts at 36 and is pointing to the left.

homozygous. one is homozygous, while two is heterozygous.

answer: 12,000

step-by-step explanation: first you ar e supposed to add. then multiply then subtract