Atank has the shape of an inverted circular cone (point at the bottom) with height 10 feet and radius 4 feet. the tank is full of water. we pump out water (to a pipe at the top of the tank) until the water level is 5 feet from the bottom. the work w required to do this is given by w= ? foot-pounds

Step-by-step explanation:

Given that tank has the shape of inverted circular cone

Height = 10 feet and radius =  4 feet

After water pumped out height = 5 ft

Hence volume of water pumped out =

Here we have r/h is constant always

Hence

Substitute to get volume of water pumped out =

Mass of water = density x volume =

Work done = force x displacement

= mass x accen x displacement

Here acceleration = gravity = 32.2 ft/sec^2

Displaement = height reduced = 5 ft

W=2912(32.2)(5)\pi =468832\pi foot -pound

b

step-by-step explanation:

u take $75 minus $60.the anwer/original($75)multiply by 100