The capacity of the milk pitcher on the counter is 9/10 liter each one pitcher has3/8 of milk in it and the other pitcher has 5/12 of a liter milk in it much is there altogether?

57/80L

Step-by-step explanation:

Given that the capacity (i.e maximum possible volume) of a pitcher is 9/10L

1st Pitcher is 3/8 full of milk

Hence Vol of milk in 1st pitcher = 9/10 x 3/8 = 27/80L

2nd Pitcher is 5/12 full of milk

Hence Vol of milk in 2nd pitcher = 9/10 x 5/12 = 3/8 = 30/80L

Total volume = 27/80 + 30/80 = 57/80L

step-by-step explanation:

1

i would say b) is your answer

sorry if im wrong

step-by-step explanation: