Problem carroll bikes 111 kilometer east, 444 kilometers north, and then 555 kilometers east again. how far is carroll from her starting position, to the nearest tenth of a kilometer?

The answer to your question is: 800.4 km

Step-by-step explanation:

Data:

111 km to east

444 km to north

555 km to east

How far is from her starting position?

See the picture please

To do this problem, we must to find the hypotenuse of a right triangle where one cathetus is 444 km and the other one is the sum of 111 and 555km.

them the pythagorean theorem says c² = a² + b²

                                                              c² = 444² + (111+555)²

                                                               c² = 444² + 666²

                                                                c² = 197136  + 443556

                                                               c² = 640692

                                                                c = 800.4 km

$8

step-by-step explanation:

it is pretty much backwards.

you take the 4x2 multiply that, and that is = $8