Asquare and a rectangle have the same perimeters. the length of a side of the square is 4x — 1. the length of the rectangle is 2x + 2 and the width is 2x. write and solve an equation to find x.

the answer for this question is 38

jml angle lkj & angle mj = lm

the answer is "add 2y and y"

step-by-step explanation:

you need to collect the like terms first.

18 units²

step-by-step explanation:

first let's find altitude bd using the distance formula

d = √((y₂ - y₁)² + (x₂ - x₁)²)

bd = √((0 - -3)² + (0 - 3)²)

bd = √18

given the placement of points a and c, we can denote that point d bisects segment ac.

we will call ac the base.

using the distance formula

ac = √((0 - 6)² + (-6 - 0)²)

ac = √72

knowing our base and our height, we can plug these into our triangle area formula

area = (b * h)/2

area = (√18 * √72) / 2

area = (√1296) / 2

area = 36 / 2

area = 18 units²