The factorization of x2 + 3x – 4 is modeled with algebra tiles. an algebra tile configuration. 2 tiles are in the factor 1 spot: 1 is labeled + x, 1 is labeled negative. 5 tiles are in the factor 2 spot: 1 is labeled + x and 4 are labeled +. 10 tiles are in the product spot: 1 is labeled + x squared, 1 is labeled negative x, the 4 tiles below + x squared are labeled + x, and the 4 tiles below the negative x tiles are labeled negative. what are the factors of x2 + 3x – 4?

The factors of x^2+3x-4 are (x-1)(x+4)

Step-by-step explanation:

We have to find the factors of x^2+3x-4

As we know that this is a quadratic equation.

So we have to find the roots first.

The roots are -1 and 4.

Now completing the quadratic formula using the roots we have :

x^2+4x-x-4

Make a pair of first two terms and last two terms:

(x^2+4x)-(x+4)

Now take out the common from each pair:

x(x+4)-1(x+4)

(x-1)(x+4)

Thus the factors of x^2+3x-4 are (x-1)(x+4)

2? if not the correct answer you might need to provide more information

step-by-step explanation: