The graph of the equation below is a circle. what is the length of the radius of the circle?
(x-6)2 + (y + 5)2 = 152

Step-by-step explanation:

hello :

an equation of the circle Center at the A(a,b) and ridus : r is :

(x-a)² +(y-b)² = r²

in this exercice r² =15²

so the length of the radius is: r = 15

A

Step-by-step explanation:

The equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k) are the coordinates of the centre and r is the radius

(x - 6)² + (y + 5)² = 15² ← is in standard form

with centre (6, - 5 ) and radius = 15

c

step-by-step explanation:

there is vertical asymptote at x = 2 and x = 0

vertical asymptote occurs at the points where the denominator is 0. so we can say that

x = 2 occurs when there is a factor (x-2) in the denominator, and

x = 0 occurs when there is a factor "x" in the denominator

thus, the denominator of the equation would have "x * (x-2)", this is option c only. that's the correct answer.

answer: the resulting cross section is a rectangle. solution: a plane parallel to the base of a triangular prism will intersect a cross section that is the same shape as its bases. so the cross section is a triangle.

step-by-step explanation: