Does the function x^2 + xy = 1 have any symmetry?

No.

Step-by-step explanation:

The equation does not match the form of any conic section.

I hope this helps you out alot, and as always, I am joyous to assist anyone at any time.

Step-by-step explanation:

Let's get this in a form we can better recognize.  we'll rearrange it until we have y by itself.

x^2 + xy = 1

xy = 1 - x^2

y = 1/x - x

There, much better.  Now,  just looking at the graph you can tell there's no symmetry along the x or y axis.  If you do not know how to check for symmetry along x=y or origin symmetry let me know.  But checking for those does show that there is no symmetry along y = x but there is origin symmetry.  

To determine that you just make all x and ys negative, and then see if you can get back to the original.  Again, let me know if you don't get determining symmetry through algebra and I'd be happy to explain each of the variations; x ais, y axis, y=x and origin.

$35.59 in pounds

step-by-step explanation:

geometric series converge the common ratio r has magnitude less than one.

which is equivalent to

for the example we need

|2-x| < 1

-1 < 2-x   and 2-x < 1

x < 3 and x > 1

we can write that

answer: 1 < x < 3

1a. common ratio r=250/25=10 > 1     diverges

1b.   r=50/100=1/2 converges

when these converge they converge to

where a is the first term.

answer: 200

1c. r=-1   so it's not the case that |r| < 1.     diverges

2a. x is the common ratio so we converge when |x|< 1

2b.   r=-10x / -2 = 5x.

we converge when

|5x| < 1

|x| < 1/5

2c.   r=3-2x

-1 < 3-2x and 3-2x < 1

-4 < -2x and 2 < 2x

x < 2 and 1 < x

1 < x < 2

2d. [/tex] r=-48x^3/12 = 4x^3[/tex]

|4x^3| < 1

|x^3| < \frac 1 4

|x| < 4^{-1/3}