Using the priority list t., t3, t., t10, t5, t3, t1, t2, t., t4, schedule the project below with two processors,
ti (2)
t5 (12)
t9 (3)
t6 (4)
t8 (9)
tio (11)
ind
17 (6)
t4 (5)
the finishing time is:
the total idle time in the schedule is:

there are 70 more legs than eyes at the dog show (196 – 126 = 70). dogs have two more legs than eyes, and humans have the same number of legs as eyes. thus 70 is twice the number of dogs at the show, so the number of dogs is half of 70, which is 35. to get the number of humans, subtract 35 from 63: 63 – 35 = 28.

step-by-step explanation:

something over 10 so ? /10

step-by-step explanation:

hard

step-by-step explanation:

lol, i have been using this product for a while and the second half of the year for a lon and the first time in a long time ago that the government has not yet received enough votes to be a good the first place in the world to be able to do it in my world life, i