Which equation represents a line that contains the point (10,-5) and is perpendicular to line y=5/4x+2

Step-by-step explanation:

A line perpendicular to another has slope

Where , m1 is the slope of the given line

and m2 is the slope of the line perpendicular to the given line !!

Given equation of line :- y = (5/4)x + 2

comparing it with equation of straight line

i.e, y = mx + c

Where m is slope of the line and c is y intercept !!

So, comparing we get m1 = 5/4

and c = 2

Also, the perpendicular line passes through the point ( 10 , - 5 )

x1 = 10

y1 = -5

Equating of the line :-

( y - y1 ) = m ( x - x1 )

So,

( y - ( -5) ) = ( -4/5) ( x - 10 )

( y + 5 ) = (-4/5) ( x - 10 )

5y + 25 = -4x + 40

4x + 5y - 15 = 0

Is ,the required equation !!

because 1.2 isnt half of 6 duh