If y varies directly as x and y is 48 when x is 48 when x is 6 which expression can be used to find the values of y when x is 2

the expression is

y=8x

Step-by-step explanation:

y varies directly as x is written as

introducing constant

y=kx

from the question, when y=48, x=6

substitute it in the formula

48=6k

making k the subject by dividing through by 6

k=8

putting the value of k in the expression,

y=8x

the value of y when x=2

y=8×2

y=16

thus the value of y when x=2 is 16.