For a standard normal distribution, find the approximate value of p(-0.78 325 1.16). use the portion of the standard normal
table below to answer the question.
z
0.00
0.16
0.22
0.78
1.00
1.16
1.78
2.00
probability
0.5000
0.5636
0.5871
0.7823
0.8413
0.8770
0.9625
0.9772

dc=6 square root of 3 and ac is 12 square root 3

c and d

step-by-step explanation:

square root of 3/2 = 18/c

cross multiply to get 18*2=√3*c

36/√3 * √3/√3 = c

c= 36*√3/3

c=12√3

what is the rest of the question? ?

answer: the correct option is d.

explanation:

it is given that the triangle j'k'l' shown on the grid below is a dilation of triangle jkl using the origin as the center of dilation.

from the given graph it is noticed that k(4,8) and k'(2,4). let origin is defined by o and scale factor is defined by k, then

    (1)

distance formula,

put these values in equation (1).

therefore scale factor is     and option d is correct.