Ticket sales for a spaghetti dinner total $2475. there are four times as many adult tickets sold as children's tickets. the prices of the tickets for adults and children are $10 and $5, respectively. find the number of children's tickets sold.

55 children's tickets

Step-by-step explanation:

Let the number of adult tickets sold  = a

Let the number of children tickets sold = c

As per the statement "The adult tickets were sold four times as many as children's tickets".the equation will be

a = 4c ----- (1)

As per second statement "the prices of the tickets for adults and children are $10 and $5 respectively."

The total price of the adult tickets = 10a

the total price of the children tickets = 5c

total tickets were sold for = $2,475

So the equation will be

10a + 5c = 2,475 ------(2)

Now substitute the the value of a from equation (1) to equation (2).

10(4c) + 5c = 2,475

40c + 5 c = 2,475

45c = 2,475

c =

c = 55

The number of children's tickets 55.

correct answer is infinitely many solutions

step-by-step explanation:

2(2x + 3) = -4 + 2(2x + 5)

solving the above equation:

4x + 6 = -4 +4x +10

combining like terms

4x -4x = -4+10-6

0=0

since both sides are 0=0, we end up into true statement it means it has infinite many solutions.

so correct answer is infinitely many solutions

i need more info. are you looked to see there mph? how much they deliver? how far they go?

step-by-step explanation: