The width of a rectangle is 1 2 of its length. what are the sides of the rectangle if its perimeter is 63 in.?the width is in, the length is in

The length of the rectangle is 21 inches, the width of the rectangle is 10.5 inches

Step-by-step explanation:

Let x inches be the length of the rectangle, then the width of the rectangle is inches.

The perimeter of the rectangle is the sum of all sides' lengths:

Thus,

Hence, the length of the rectangle is 21 inches, the width of the rectangle is 10.5 inches.

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15