subject
Mathematics, 13.09.2019 17:10 breannaasmith1122

Let s(x) = x^2 - cos x. a prove that has exactly one root on the interval (0.5, 0.9]. b) use the bisection method starting with the interval (0.5, 0.9] to approximate the solution to within 0.001 . show a, b & midpt at each step. justify why the number of iterations performed is sufficient. c) determine the number of steps of the bisection method that would be necessary to guarantee an absolute error of less than 10 -". (note that n steps means that the nth midpoint is accepted as the approximation.)

ansver
Answers: 3

Another question on Mathematics

question
Mathematics, 21.06.2019 18:00
If you had $1,900,000, how many days would it take you to spend all if you spent $1 a second. (there are 86,400 seconds in a day)
Answers: 1
question
Mathematics, 21.06.2019 18:40
The ratios 3: 9, 4: 12, 5: 15, and 6: 18 are a pattern of equivalent ratios in the ratio table. which is another ratio in this pattern?
Answers: 1
question
Mathematics, 21.06.2019 19:30
[15 points]find the least common multiple of the expressions: 1. 3x^2, 6x - 18 2. 5x, 5x(x +2) 3. x^2 - 9, x + 3 4. x^2 - 3x - 10, x + 2 explain if possible
Answers: 3
question
Mathematics, 21.06.2019 21:00
Solve this problem! extra ! 3025/5.5 = a/90.75 / = fraction
Answers: 3
You know the right answer?
Let s(x) = x^2 - cos x. a prove that has exactly one root on the interval (0.5, 0.9]. b) use the bis...
Questions
question
Mathematics, 02.04.2021 02:20
question
Mathematics, 02.04.2021 02:20
Questions on the website: 13722361