Assume that the sales of a certain appliance dealer can be approximaed y sraig were $6000 in 1982 and $ 64,000 in 1987. let x - o represent 1982 find the equation giving yearly alessand then use it to predict the yearly sales in 1990.

Yearly sales in 1990: $98,800.

Step-by-step explanation:

We have been given that the sales of a certain appliance dealer can be approximated by a straight line. Sales were $6000 in 1982 and $ 64,000 in 1987.

If at 1982, then at 1987 x will be 5.

Now, we have two points (0,6000) and (5,64000).

Now, we will represent this information in slope-intercept form of equation.

, where,

m = Slope,

b = Initial value or y-intercept.

We have been given that at , the value of y is 6,000, so it will be y-intercept.

Substitute values:

Therefore, the equation represents yearly sales.

Now, we will find difference between 1990 and 1982.

To find yearly sales in 1990, we will substitute in the equation.

Therefore, the yearly sales in 1990 would be $98,800.

the mistake in the pattern is that :

b. the decimal point was moved one too many place values each time

the correct pattern could be made by :

b. moving the decimal point to the right the same numbers of place values as the exponents

answer:

step-by-step explanation: