![[(x \vee y) \wedge (x \rightarrow z) \wedge (\neg z)]](/tpl/images/0229/9835/0af82.png)
is true, then:
is true
is true
is true
is false.
, since 
is true
is true.
is false, as 
is true.
How can this be proved to be a tautology using laws of logical equivalence?
((x ∨ y) ∧ (x → z...
Mathematics, 13.09.2019 17:30 tddreviews
How can this be proved to be a tautology using laws of logical equivalence?
((x ∨ y) ∧ (x → z) ∧ (¬z)) → y
Answers: 2
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