Greg is covering a wall with equal-sized tiles that cannot be cut
into smaller pieces. the wall is 66 inches high by 72 inches wide.
what is the largest square tile that simon can use?
a. 9 in.
b. 16 in.
c. 36 in.
d. 64 in.

C. 36 in.

Step-by-step explanation:

The wall is 66 inches high by 72 inches wide.

The tiles are

a) 9 inch square = 3 by 3

b) 16 inch square = 4 by 4

c) 36 inch square = 6 by 6

d) 64 inch square = 8 by 8

Factors of 66 = 2 x 3 x 11

Factors of 72 = 2 x 2 x 2 x 3 x 3

Now, we can see that in both 66 and 72 , we have 2 x 3 common that is 6.

And square of 6 is 36.

So, the answer is option C.

answer:

your answer is: c. 196 7/8 in^3.

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15