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Mathematics, 13.09.2019 18:30 aliami0306oyaj0n

Solve the following initial value problem: 2xyy'+y^2-4x^3=0. where y(1)=2
the answer is y= sqrt((x^4+3)/x)

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Answers: 1

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Solve the following initial value problem: 2xyy'+y^2-4x^3=0. where y(1)=2
the answer is y= sq...
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