90 ! need asap ! create a function y=f(x) that has a removable discontinuity at x=2 and a non-removable discontinuity at x=3. show work and step by step on how you got it.

step-by-step explanation:

the denominator in choice a factors to (x-2)(x+1). we have a pair of "x-2" terms that cancel leaving us with 1/(x+1). we cannot plug x = -1 into the simplified result because it leads the denominator x+1 to turn into 0.

also, we cannot plug x = 2 into p(x) for choice a either. it doesn't lead to issues for 1/(x+1) but the original function before we simplify will have x = 2 lead to a division by zero error.

a vertical asymptote is located at x = -1

the removable discontinuity happens when x = 2, so there will be a hole here.

got any answer chocies

set each factor equal to 0

4x-3 = 0

2x-1 = 0

solve for x.

4x-3=0

4x=3

x= 3/4

solve for x. 

2x-1= 0

2x= 1

x= 1/2

your answer should be 1/2 is less than or equal to x and 3/4 is greater than or equal to x

25 questions , because they start with 100.  

350-100=250 .  

. 250/10=25

step-by-step explanation:

first take off 100, then what x 10 = 250? that is your answer. (25)