April shoots an arrow upward into the air at a speed of 64 feet per second from a platform that is 11 feet high. the height of the arrow is given by the function h(t) = -16t2 + 64t + 11, where t is the time is seconds. what is the maximum height of the arrow?

Maximum height of the arrow is 203 feets

Step-by-step explanation:

It is given that,

The height of the arrow as a function of time t is given by :

..........(1)

t is in seconds

We need to find the maximum height of the arrow. For maximum height differentiating equation (1) wrt t as :

t = 2 seconds

Put the value of t in equation (1) as :

h(t) = 203 feet

So, the maximum height reached by the arrow is 203 feet. Hence, this is the required solution.

step-by-step explanation:

de-gf

hj=3x+20

ji=15x-64