Triangles are formed by the intersection of the lines y=x, y 2x, y=-2x, and y=-4. solve for angles abc and abd a d b

Answer and Step-by-step explanation:

To find the angles between the lines, we can use the formula:

tanα = |ms - mr| / | 1 + ms.mr|

where ms and mr are the linear coefficients of the lines you want to find. It always finds the smaller angle formed.

Let's find all the angles from the triangles formed.

y=x     ms = 1

y=2x   mr = 2

tanα = |1 - 2| / | 1 + 1.2|

tanα = |-1| / | 1 + 2|

tanα = |-1/3|

tanα = 1/3

α = tan⁻¹1/3

α = 18.4°

y=x     ms = 1

y=-4   mr = 0

tanα = |1 - 0| / | 1 + 1.0|

tanα = |1| / | 1 + 0|

tanα = |1/1|

tanα = 1

α = tan⁻¹1

α = 45°

y=2x     ms = 2

y=-4     mr = 0

tanα = |2 - 0| / | 1 + 2.0|

tanα = |2| / | 1 + 0|

tanα = |2/1|

tanα = 2

α = tan⁻¹2

α = 63.4°

As these 2 lines are in both triangles, the suplement of this angle is also asked, so, 180° - 63.4° = 116.6°

For y=2x and y=-4, it's the same: α = 63.4°  

y=2x     ms = 2

y=-2x     mr = -2

tanα = |2 - (-2)| / | 1 + 2.(-2)|

tanα = |4| / | 1 - 4|

tanα = |4/3|

tanα = 4/3

α = tan⁻¹ 4/3

α = 53.1°

2

step-by-step explanation:

hence, the required result is

step-by-step explanation:

suppose we have two matrices a and b

we will assume the two matrices

we have to compute b-a which means subtracting corresponding elements of a from b.

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