What weight of magnesium chloride (mgcl2, formula weight 95.3; mg2, atomic weight = 243; cl, atomic weight-35.5) is required to prepare 1,000 ml of a solution that contains 5.0 meq of magnesium?

238.25 mg

Step-by-step explanation:

Given:

Molar mass of MgCl₂ = 95.3

atomic weight of Mg₂ = 243

Atomic weight of Cl = 35.5

Volume of solution required = 5.0 mEq of magnesium

Now,

mEq =

on substituting the values, we get

5 =

or

weight of magnesium chloride = 238.25 mg

Therefore,

the required mass of MgCl₂ is 238.25 mg

idk sry

step-by-step explanation:

1) c 2143.6 cm

2) c 113.0 m

3) a 33.5 ft

4)   d 2 cm

5) c 20 mm

6) 180 in

7) d 120 ft