Fix a matrix a and a vector b. suppose that y is any solution of the homogeneous system ax=0 and that z is any solution of the system ax=b. show that y+z is also a solution of the system ax=b.

Since y is a solution of the homogeneus system then satisfies Ay=0.

Since z is a solution of the system Ax=b then satisfies Az=b.

Now, we will show that A(y+z)=b.

Observe that A(y+z)=Ay+Az by properties of the product of matrices.

By hypotesis Ay=0 and Az=b.

Then A(y+z)=Ay+Az=0+b=b.

Then A(y+z)=b, this show that y+z is a solution of the system Ax=b.

i think the answer is .36

step-by-step explanation:

what i did was only 2.88 divided by 8

d. bc = 12 and ef = 16

step-by-step explanation:

we are given that δabc : δdef such that .

also, it is given that

so, from the options, we need that .

a.

b.

c.  

d.

as, we can see that only option d gives the same ratio as i.e. .

hence, the possible lengths are bc = 12 and ef = 16.