Prove that if n is a perfect square, then n+1 can never be a perfect square

Proved

Step-by-step explanation:

To prove that if n is a perfect square, then n+1 can never be a perfect square

Let n be a perfect square

Let

Subtract to get

Solution is y+x=y-x=1

This gives x=0

So only 0 and 1 are consecutive integers which are perfect squares

No other integer satisfies y+x=y-x=1

b.an increase in a causes b to decrease

14

step-by-step explanation: