Suppose that there are two types of tickets to a show advance and same day the combined cost of one advance ticket and one same day ticket is $65 for one performance 35 advance tickets and 40 same day tickets were sold me the total amount paid for the tickets was $2400 what was the price of each kind of ticket

x = -3

y = -18

step-by-step explanation:

to solve by substitution, substitute one variable and solve for the other. then substitute again to find the remaining variable.

x-1/3(3x-9) = -3 since y=3x-9 substittute y.

x-1/3(3x-9)=-3

x + x +3 = -3

2x+3=-3

2x+3-3= -3-3

2x=-6

x=-3

substitute again into y=3x-9

y=3(-3)-9

y=-9-9

y=-18

step-by-step explanation:

options

one set of data has more variation than the other. hope this !