Consider the line y=-5/9x+6
find the equation of the line that is parallel to this line and passes through the point (9, -3).
find the equation of the line that is perpendicular to this line and passes through the point (9, -3

See below in bold.

Step-by-step explanation:

Use the point-slope form of a straight line

y - y1 = m(x - x1)

Here m = -5/9 , x1 = 9 and y1 = -3:, so

y - -3 = -5/9(x - 9)

y + 3 = -5/9x + 5

y = -5/9x + 2  is the equation parallel to the given line.

The  line perpendicular to the given line will have a slope of - 1 / -5/9

= 9/5 so its equation is

y  + 3 = 9/5(x - 9)

y = 9/5x - 81/5 - 3

y = 9/5x - 96/5 .

well the 1 and -1 are always after the 0 and the 0 is inthe middle. s thats what i would guess. but i dont know what a slope of 2 is sorry

step-by-step explanation:

the answer would be 1 1/72

step-by-step explanation:

you can rewrite the equation by separating the parts and then solving individually:

10-9=1

1/8 - 1/9=

find l c d and then combine:

1 1/72