Acomputer uses passwords that consist of the 26 letters (a-z) and the 10 numbers (0-9). the lettersare not case-sensitive (i. e., there is no difference between upper- and lower-) how many different passwords are possible if exactly 6 characters (letters or numbers) are required?

Step-by-step explanation:

If the password was one character long, you would have 36 options.

If the password was two characters long, you would have 36*36 (a+ any random letter, or b+ any random letter. etc.) options

If the password was three characters long, you would have 36*(36*36) options (a two characters password, plus another character).

...

At six characters, you have 36*36*36*36*36*36, or that is 2 176 782 336

a) y = -3x +2

b) y = 1/2x -6

these 2 can be combined into one equation.

-3x +2 = .5x -6

8 = 3.5x

x = 8 / 3.5 = 2.2857142857

y = -3 * (8 / 3.5) +2

y = (-24 / 3.5) + 2

y = -4.8571428571

step-by-step explanation:

yes   because as the functions are graphed they eventually will intersect unless otherwise

step-by-step explanation: