Aand b are discrete random variables. a can take on one of 20 possible values. b can take on one of 64 possible values. (in other words, the size of domain ( a ) is 20, and the size of domain ( b ) is 64.) how many possible outcomes does the joint distribution p ( a, b ) define probabilities for?

It defines 1280 possible outcomes

Step-by-step explanation:

A can take on one of 20 possible values.Then, B can take on one of 64 possible values

The form to choose these pairs of outcomes are

(Possible values from A) x (Possible values from B) = 20 x 64 = 1280

Also the sum of these 1280 pairs of values must be equal to 1 because P(A,B) it is a joint distribution of probability.

We sum this 1280 pairs of values because A and B are discrete random variables.Otherwise we would use integrals.

t = 3

step-by-step explanation:

put t = 3 in this expression :

(3²-1)(3²-2)(3² - 3)(3² - 4) = 8×7×6×5 = 56×30 = 1680

ok

step-by-step explanation: